Solving a Linear Systes of Equations Using python

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    Solving a Linear Systes of Equations Using python

    Solving linear systems of equations is straightforward using the scipy command linalg.solve. This command expects an input matrix and a right-hand-side vector. The solution vector is then computed. An option for entering a symmetrix matrix is offered which can speed up the processing when applicable. As an example, suppose it is desired to solve the following simultaneous equations:
    \begin{eqnarray*} x+3y+5z & = & 10\\ 2x+5y+z & = & 8\\ 2x+3y+8z & = & 3\end{eqnarray*}
    We could find the solution vector using a matrix inverse:
    \[ \left[\begin{array}{c} x\\ y\\ z\end{array}\right]=\left[\begin{array}{ccc} 1 & 3 & 5\\ 2 & 5 & 1\\ 2 & 3 & 8\end{array}\right]^{-1}\left[\begin{array}{c} 10\\ 8\\ 3\end{array}\right]=\frac{1}{25}\left[\begin{array}{c} -232\\ 129\\ 19\end{array}\right]=\left[\begin{array}{c} -9.28\\ 5.16\\ 0.76\end{array}\right].\]
    However, it is better to use the linalg.solve command which can be faster and more numerically stable. In this case it however gives the same answer as shown in the following example:
    >>> import numpy as np
    >>> from scipy import linalg
    >>> A = np.array([[1,2],[3,4]])
    >>> A
    array([[1, 2],
    [3, 4]])
    >>> b = np.array([[5],[6]])
    >>> b
    array([[5],
    [6]])
    >>> linalg.inv(A).dot(b) #slow
    array([[-4. ],
    [ 4.5]]
    >>> A.dot(linalg.inv(A).dot(b))-b #check
    array([[ 8.88178420e-16],
    [ 2.66453526e-15]])
    >>> np.linalg.solve(A,b) #fast
    array([[-4. ],
    [ 4.5]])
    >>> A.dot(np.linalg.solve(A,b))-b #check
    array([[ 0.],
    [ 0.]])


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